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360x-2x^2=x
We move all terms to the left:
360x-2x^2-(x)=0
We add all the numbers together, and all the variables
-2x^2+359x=0
a = -2; b = 359; c = 0;
Δ = b2-4ac
Δ = 3592-4·(-2)·0
Δ = 128881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{128881}=359$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(359)-359}{2*-2}=\frac{-718}{-4} =179+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(359)+359}{2*-2}=\frac{0}{-4} =0 $
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